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0.03x^2=1.2x
We move all terms to the left:
0.03x^2-(1.2x)=0
We add all the numbers together, and all the variables
0.03x^2-(+1.2x)=0
We get rid of parentheses
0.03x^2-1.2x=0
a = 0.03; b = -1.2; c = 0;
Δ = b2-4ac
Δ = -1.22-4·0.03·0
Δ = 1.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.2)-\sqrt{1.44}}{2*0.03}=\frac{1.2-\sqrt{1.44}}{0.06} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.2)+\sqrt{1.44}}{2*0.03}=\frac{1.2+\sqrt{1.44}}{0.06} $
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